25=b^2/3

Solution for 25=b^2/3 equation:

25=b^2/3

We move all terms to the left:

25-(b^2/3)=0

We get rid of parentheses

-b^2/3+25=0

We multiply all the terms by the denominator


-b^2+25*3=0

We add all the numbers together, and all the variables

-1b^2+75=0

a = -1; b = 0; c = +75;
Δ = b2-4ac
Δ = 02-4·(-1)·75
Δ = 300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{300}=\sqrt{100*3}=\sqrt{100}*\sqrt{3}=10\sqrt{3}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{3}}{2*-1}=\frac{0-10\sqrt{3}}{-2}
=-\frac{10\sqrt{3}}{-2}
=-\frac{5\sqrt{3}}{-1}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{3}}{2*-1}=\frac{0+10\sqrt{3}}{-2}
=\frac{10\sqrt{3}}{-2}
=\frac{5\sqrt{3}}{-1}
$